Tuesday, July 14, 2009

Finding the midpoint? Please help!!!?

Points are: (7^1/2, 3 3^1/2), (-7^1/2, -3^1/2)





Please explain as thouroughly as possible, I'm stuck on this problem and the tutor is closed Monday b/c of Labor Day. Thanks again!

Finding the midpoint? Please help!!!?
Midpoint= (Average of X values, average of Y values)





Since the X points are equal distances from 0 (aka one is positive, the other the same value but negative), the midpoint must be at 0.


(7^.5 + -7^.5)/2 = 0/2 = 0





For the Y values:


(3*3^.5 + -3^.5)/2=(2*3^.5)/2=3^.5





Midpoint is therefore: (0 , 3^.5)
Reply:ghstomahawks is correct.





brooke calculates something different





for simplicity let y=0 :





---A-----midpoint------B





suppose A =10, B=20 then according to brook (20-10)/2 =5 which is the length from A to m and also from m to B.





So according to brooke the midpoint lies not between A and B








ghstomahawks calculates the coordinates of the middle :


(10 + 20 )/2 = 15.


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